0=4.9t^2+2t-950

Solution for 0=4.9t^2+2t-950 equation:

0=4.9t^2+2t-950

We move all terms to the left:

0-(4.9t^2+2t-950)=0

We add all the numbers together, and all the variables

-(4.9t^2+2t-950)=0

We get rid of parentheses

-4.9t^2-2t+950=0

a = -4.9; b = -2; c = +950;
Δ = b2-4ac
Δ = -22-4·(-4.9)·950
Δ = 18624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18624}=\sqrt{64*291}=\sqrt{64}*\sqrt{291}=8\sqrt{291}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-8\sqrt{291}}{2*-4.9}=\frac{2-8\sqrt{291}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+8\sqrt{291}}{2*-4.9}=\frac{2+8\sqrt{291}}{-9.8}
$